--distance to geo-sync--

    i have been meaning to post this one, for a looong time, but the time was not right, until now...


    distance to geo-sync--


     (pounds)       (foot-pounds)               (feet)
     (weight)   -        (force)          =      (distance)
      2000      -         1900           =          100



  interposed distance to geo-sync--

   (pounds)          (feet)            (foot-pounds)
   (weight)    -  (distance)  =         (force)
     2000      -      100       =          1900


  distance to geo-sync inverted--

      (feet)            (foot-pounds)           (pounds)
  (distance)   +        (force)          =      (weight)
      100        +        1900            =        2000
 

   distance to geo-sync w/drag--


      (pounds)       (pounds % sq inches)    (foot-pounds)       (distance)
      (weight)   +   (weight % sq inches)  -      (force)        =      (feet)
       2000      +     2000 % 2000  = 1   -      1900          =        99


    distance to geo-sync for use within the atmosphere--

     some folks may have noticed, that there seems to be a "glitch", in "distance to geo-sync"... if you use different combinations of variables...here is the calc for objects within the atmosphere that are not in geo-sync in space( the lateral forces are a bit different than in space)--

    interposed distance to geo-sync--

       (pounds)          (feet)            (foot-pounds)
       (weight)   -   (distance)    =       (force)
         100       -       100         =           0              this is not correct--(if in atmosphere)

   atmospheric straight drop distance value principal--

   the distance( in atmosphere), of an object dropped straight down, always has the value of 1 foot--



    example--

     (pounds)          (feet)             (foot-pounds)
     (weight)   -   (distance)   =        (force)
       100      -          1          =          99


       lab experiment to verify interposed distance to geo-sync--

    pick-up a tork-wrench( with appropriate cert... from the chaps at "loyds of london"), use tork-wrench on the lug-nut of a vehicle( preferably at NASA), make sure the wrench is 1 foot off the ground...(humor, as all distances from the earth's crust "in atmo", are the value of 1 foot)...then balance two cans of soda( "coca-cola", or other), on the end of the tork-wrench, 1 foot-pound of tork should result--

best wishes, john kruschke--

   (cs)